#### Answer

$x=1$

#### Work Step by Step

$\displaystyle \frac{2x}{x^{2}+1}=1$
We cross-multiply:
$2x=x^{2}+1$
$x^{2}-2x+1=0$
And solve by factoring:
$(x-1)^{2}=0$
$x=1$

Published by
Brooks Cole

ISBN 10:
1305115546

ISBN 13:
978-1-30511-554-5

$x=1$

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