## College Algebra 7th Edition

$x=0$ or $x=\pm\sqrt{2}$
We solve by factoring out $6x$: $6x^{5}-24x=0$ $6x(x^{4}-4)=0$ $6x(x^{2}+2)(x^{2}-2)=0$ $6x=0$ or $x^2+2=0$ or $x^2-2=0$ $x=0$ or $x=\pm\sqrt{2}$ (The middle equation, $x^2+2=0$ has no real solution.)