College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.6 - Solving Other Types of Equations - 1.6 Exercises - Page 138: 26

Answer

$m=\pm\sqrt{85/3}$

Work Step by Step

$\displaystyle \frac{10}{m+5}+15=3m$ We multiply through by $m+5$ and solve: $10+15(m+5)=3m(m+5)$ $10+15m+75=3m^2+15m$ $10+15m+75-3m^2-15m=0$ $-3m^2+85=0$ $m^2=-85/-3=85/3$ $m=\pm\sqrt{85/3}$
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