## College Algebra 7th Edition

$m=\pm\sqrt{85/3}$
$\displaystyle \frac{10}{m+5}+15=3m$ We multiply through by $m+5$ and solve: $10+15(m+5)=3m(m+5)$ $10+15m+75=3m^2+15m$ $10+15m+75-3m^2-15m=0$ $-3m^2+85=0$ $m^2=-85/-3=85/3$ $m=\pm\sqrt{85/3}$