College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises - Page 103: 89

Answer

See below.

Work Step by Step

The standard form of the equation of a circle is: $(x-a)^2+(y-b)^2=r^2$ where $(a,b)$ is the center of the circle and $r$ is the radius. Hence, here we have: $x^2+y^2-0.5x+0.5y=0.125\\(x-0.25)^2-0.25^2+(y+0.25)^2-0.25^2=0.125\\(x-0.25)^2+(y+0.25)^2=0.25=0.5^2$ Thus, the center is at $(0.25,-0.25)$ and the radius is $0.5$.
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