Answer
The equation represents a circle
$ (x+\frac{1}{2})^2+(y^2+0)^2=(\frac{1}{2})^2$
with center $(-\frac{1}{2},0)$ and radius is $\frac{1}{2}$
Work Step by Step
$\underline{\textbf{Given equation}}$
$x^2+y^2+x=0$
$\Rightarrow x^2+x+y^2=0$
$\Rightarrow (x^2+x)+(y^2)=0$
$\Rightarrow (x^2+x+\frac{1}{4})+(y^2)=\frac{1}{4}$
$\Rightarrow (x+\frac{1}{2})^2+(y^2+0)^2=(\frac{1}{2})^2$
Which is the standard form for the equation of circle with center $(-\frac{1}{2},0)$ and radius is $\frac{1}{2}$