College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises: 81

Answer

$(x+2)^2+(y-2)^2=4$

Work Step by Step

RECALL: The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x-h)^2+(y-k)^2=r^2$. The graph shows that the circle has its center at $(-2, 2)$ and a radius of $2$ units. Thus, the equation of the circle is: $[x-(-2)]^2+(y-2)^2=2^2 \\(x+2)^2+(y-2)^2=4$
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