#### Answer

$(x+1)^2+(y-1)^2=9$

#### Work Step by Step

RECALL:
The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x-h)^2+(y-k)^2=r^2$.
The graph shows that the circle has its center at $(-1, 1)$ and a radius of $3$ units.
Thus, the equation of the circle is:
$[x-(-1)]^2+(y-1)^2=3^2
\\(x+1)^2+(y-1)^2=9$