## College Algebra 7th Edition

$(x+1)^2+(y-1)^2=9$
RECALL: The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x-h)^2+(y-k)^2=r^2$. The graph shows that the circle has its center at $(-1, 1)$ and a radius of $3$ units. Thus, the equation of the circle is: $[x-(-1)]^2+(y-1)^2=3^2 \\(x+1)^2+(y-1)^2=9$