College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 8

Answer

$13$

Work Step by Step

$\sqrt {144+25}$ $=\sqrt {169}$ $=13$ because $13^{2} = 169$
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