College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 18



Work Step by Step

$\sqrt{10x} \cdot \sqrt{8x}$ By the product rule for square roots $=\sqrt{10x \cdot 8x}$ $=\sqrt{80x^{2}}$ $=\sqrt{16\cdot5\cdot x^{2}}$ $=\sqrt{16} \cdot \sqrt{x^{2}} \cdot \sqrt{5}$ $=4x\sqrt{5}$
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