College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 73



Work Step by Step

$\frac{\sqrt[5] 64x^{6}}{\sqrt[5] 2x}=\sqrt[5] \frac{64x^{6}}{2x}=\sqrt[5] 32x^{5}=2x$ We know that $\sqrt[5] 32x^{5}=2x$, because $(2x)^{5}=2^{5}x^{5}=32x^{5}$.
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