Answer
$2x$
Work Step by Step
$\frac{\sqrt[5] 64x^{6}}{\sqrt[5] 2x}=\sqrt[5] \frac{64x^{6}}{2x}=\sqrt[5] 32x^{5}=2x$
We know that $\sqrt[5] 32x^{5}=2x$, because $(2x)^{5}=2^{5}x^{5}=32x^{5}$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 73
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