College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 65



Work Step by Step

We know that $\sqrt[5] -\frac{1}{32}=-\frac{1}{2}$, because $(-\frac{1}{2})^{5}=-\frac{1}{2}\times-\frac{1}{2}\times-\frac{1}{2}\times-\frac{1}{2}\times-\frac{1}{2}=-\frac{1}{32}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.