College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 30



Work Step by Step

$\frac{\sqrt{24x^{4}}}{{\sqrt{3x}}}$ By the quotient rule for square roots $=\sqrt{\frac{24x^{4}}{3x}}$ $=\sqrt{8x^{3}}$ $=\sqrt{4 \cdot 2 \cdot x^{2} \cdot x}$ $=\sqrt{4} \cdot \sqrt{x^{2}} \cdot \sqrt{2x}$ $=2x\sqrt{2x}$
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