College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 48: 16



Work Step by Step

$\sqrt{125x^2}$ $=\sqrt{25\cdot3\cdot x^{2}}$ $=\sqrt{25}\cdot \sqrt{x^{2}} \cdot \sqrt{3}$ $=5x\sqrt{3}$
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