Answer
See below.
Work Step by Step
By the text of the exercise:
$a_1=4$
$a_2=2a_1+3=2\cdot4+3=11$
$a_3=2a_2+3=2\cdot11+3=25$
$a_4=2a_3+3=2\cdot25+3=53$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Summary, Review, and Test - Review Exercises - Page 788: 6
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
