College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 788: 21


See below.

Work Step by Step

The nth term of a geometric sequence can be obtained by the following formula: $a_n=a_1+(nāˆ’1)d,$ where $a_1$ is the first term and $d$ is the common difference. As we can see here:$a_1=3,d=-5$. Thus $a_n=3+(n-1)-5=3-5n+5=8-5n$ Hence here: $a_{20}8-5\cdot20=8-100=-92$
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