College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 788: 13

Answer

See below.

Work Step by Step

$a_n=-4-5(n-1)$, thus $a_1=-4-5(1-1)=-4-5\cdot0=-4-0=-4$ $a_2=-4-5(2-1)=-4-5\cdot1=-4-5=-9$ $a_3=-4-5(3-1)=-4-5\cdot2=-4-10=-14$ $a_4=-4-5(4-1)=-4-5\cdot3=-4-15=-19$ $a_5=-4-5(5-1)=-4-5\cdot4=-4-20=-24$ $a_6=-4-5(6-1)=-4-5\cdot5=-4-25=-29$
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