College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 788: 15

Answer

See below.

Work Step by Step

$a_n=a_{n-1}+5$ and $a_1=-2$ thus $a_2=a_1+5=-2+5=3$ $a_3=a_2+5=3+5=8$ $a_4=a_3+5=8+5=13$ $a_5=a_4+5=13+5=18$ $a_6=a_5+5=18+5=23$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.