College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 788: 10

Answer

$\sum_{i=1}^{15} \frac{i}{i+2}$

Work Step by Step

The numerator starts at $1$ and increases by $1$ at each term until it reaches $15$, the denominator starts at $3$ and increases by $1$ at each term until it reaches $17$. Thus the formula: $\sum_{i=1}^{15} \frac{i}{i+2}$
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