Answer
$\frac{1}{2},\frac{1}{4},0,-\frac{1}{4},-\frac{1}{2},-\frac{3}{4}$
Work Step by Step
To solve this problem, use formula for the nth term.
$a_{n}=a_{1}+d(n-1)$ we will put values from 1 to 6 into n.
$a_{n}=\frac{3}{4}+(-\frac{1}{4})(n-1)$