Answer
Given
$a_{n}$ = $a_{n - 1}$ + 5.
$a_{1}$, the first term = 6
$20^{th}$ term of sequence = 101
Work Step by Step
Given
$a_{n}$ = $a_{n - 1}$ + 5.
$a_{1}$, the first term = 6
$2^{nd}$ term of sequence = $a_{1}$ + 5 = 6 + 5 = 11
$3^{rd}$ term of sequence = $a_{2}$ + 5 = 11 + 5 = 16
$4^{th}$ term of sequence = $a_{3}$ + 5 = 16 + 5 = 21
$5^{th}$ term of sequence = $a_{4}$ + 5 = 21 + 5 = 26
$6^{th}$ term of sequence = $a_{5}$ + 5 = 26 + 5 = 31
$7^{th}$ term of sequence = $a_{6}$ + 5 = 31 + 5 = 36
$8^{th}$ term of sequence = $a_{7}$ + 5 = 36 + 5 = 41
$9^{th}$ term of sequence = $a_{8}$ + 5 = 41 + 5 = 46
$10^{th}$ term of sequence = $a_{9}$ + 5 = 46 + 5 = 51
$11^{th}$ term of sequence = $a_{10}$ + 5 = 51 + 5 = 56
$12^{th}$ term of sequence = $a_{11}$ + 5 = 56 + 5 = 61
$13^{th}$ term of sequence = $a_{12}$ + 35= 61 + 5 = 66
$14^{th}$ term of sequence = $a_{13}$ + 5 = 66 + 5 = 71
$15^{th}$ term of sequence = $a_{14}$ + 5 = 71 + 5 = 76
$16^{th}$ term of sequence = $a_{15}$ + 5 = 76 + 5 = 81
$17^{th}$ term of sequence = $a_{16}$ + 5= 81 + 5 = 86
$18^{th}$ term of sequence = $a_{17}$ + 5 = 86 + 5 = 91
$19^{th}$ term of sequence = $a_{18}$ + 5 = 91 + 5 = 96
$20^{th}$ term of sequence = $a_{19}$ + 5 = 96 + 5 = 101