## College Algebra (6th Edition)

Given $a_{n}$ = $a_{n - 1}$ + 5. $a_{1}$, the first term = 6 $20^{th}$ term of sequence = 101
Given $a_{n}$ = $a_{n - 1}$ + 5. $a_{1}$, the first term = 6 $2^{nd}$ term of sequence = $a_{1}$ + 5 = 6 + 5 = 11 $3^{rd}$ term of sequence = $a_{2}$ + 5 = 11 + 5 = 16 $4^{th}$ term of sequence = $a_{3}$ + 5 = 16 + 5 = 21 $5^{th}$ term of sequence = $a_{4}$ + 5 = 21 + 5 = 26 $6^{th}$ term of sequence = $a_{5}$ + 5 = 26 + 5 = 31 $7^{th}$ term of sequence = $a_{6}$ + 5 = 31 + 5 = 36 $8^{th}$ term of sequence = $a_{7}$ + 5 = 36 + 5 = 41 $9^{th}$ term of sequence = $a_{8}$ + 5 = 41 + 5 = 46 $10^{th}$ term of sequence = $a_{9}$ + 5 = 46 + 5 = 51 $11^{th}$ term of sequence = $a_{10}$ + 5 = 51 + 5 = 56 $12^{th}$ term of sequence = $a_{11}$ + 5 = 56 + 5 = 61 $13^{th}$ term of sequence = $a_{12}$ + 35= 61 + 5 = 66 $14^{th}$ term of sequence = $a_{13}$ + 5 = 66 + 5 = 71 $15^{th}$ term of sequence = $a_{14}$ + 5 = 71 + 5 = 76 $16^{th}$ term of sequence = $a_{15}$ + 5 = 76 + 5 = 81 $17^{th}$ term of sequence = $a_{16}$ + 5= 81 + 5 = 86 $18^{th}$ term of sequence = $a_{17}$ + 5 = 86 + 5 = 91 $19^{th}$ term of sequence = $a_{18}$ + 5 = 91 + 5 = 96 $20^{th}$ term of sequence = $a_{19}$ + 5 = 96 + 5 = 101