College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.2 - Page 724: 34

Answer

Given $a_{n}$ = $a_{n - 1}$ - 12. $a_{1}$, the first term = 24 $20^{th}$ term of sequence = -204

Work Step by Step

Given $a_{n}$ = $a_{n - 1}$ - 12. $a_{1}$, the first term = 24 $2^{nd}$ term of sequence = $a_{1}$ - 12 = 24 - 12 = 12 $3^{rd}$ term of sequence = $a_{2}$ - 12 = 12 - 12 = 0 $4^{th}$ term of sequence = $a_{3}$ - 12 = 0 - 12 = -12 $5^{th}$ term of sequence = $a_{4}$ - 12 = -12 - 12 = -24 $6^{th}$ term of sequence = $a_{5}$ - 12 = -24 - 12 = -36 $7^{th}$ term of sequence = $a_{6}$ - 12 = -36 - 12 = -48 $8^{th}$ term of sequence = $a_{7}$ - 12 = -48 - 12 = -60 $9^{th}$ term of sequence = $a_{8}$ - 12 = -60 - 12 = -72 $10^{th}$ term of sequence = $a_{9}$ - 12 = -72 - 12 = -84 $11^{th}$ term of sequence = $a_{10}$ - 12 = -84 - 12 = -96 $12^{th}$ term of sequence = $a_{11}$ - 12 = -96 - 12 = -108 $13^{th}$ term of sequence = $a_{12}$ - 12 = -108 - 12 = -120 $14^{th}$ term of sequence = $a_{13}$ - 12 = -120 - 12 = -132 $15^{th}$ term of sequence = $a_{14}$ - 12 = -132 - 12 = -144 $16^{th}$ term of sequence = $a_{15}$ - 12 = -144 - 12 = -156 $17^{th}$ term of sequence = $a_{16}$ - 12 = -156 - 12 = -168 $18^{th}$ term of sequence = $a_{17}$ - 12 = -168 - 12 = -180 $19^{th}$ term of sequence = $a_{18}$ - 12 = -180 - 12 = -192 $20^{th}$ term of sequence = $a_{19}$ - 12 = -192 - 12 = -204
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