College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.2 - Page 724: 39

Answer

5050

Work Step by Step

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + . . . . .+ 100 First term $a_{1}$ = 1 Common difference d = 1 Sum of n terms = $\frac{n}{2}$($a_{1}$ + $a_{n}$) Sum of first 100 natural numbers = $\frac{100}{2}$(1 + 100) = 50$\times$101 = 5050
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