College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Mid-Chapter Check Point - Page 743: 7

Answer

General term($n^{th}$ term) = 2 - $\frac{1}{2}$ n Indicated term $a_{30}$ = -13

Work Step by Step

The given sequence = $\frac{3}{2}$, 1, $\frac{1}{2}$, 0,..........;$a_{30}$ From above we observe $a_{1}$ = $\frac{3}{2}$ common difference (d) = 0 - $\frac{1}{2}$ = $\frac{1}{2}$ - 1 = 1 - $\frac{3}{2}$ = -$\frac{1}{2}$ General term($n^{th}$ term) = $a_{n}$ = $\frac{3}{2}$ +(n-1)(-$\frac{1}{2}$) = $\frac{3}{2}$ - $\frac{1}{2}$n + $\frac{1}{2}$ = 2 - $\frac{1}{2}$ n Indicated term $a_{30}$ = 2 - $\frac{1}{2}$ $\times$ 30 = 2 - 15 = -13
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.