College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Mid-Chapter Check Point - Page 743: 9

Answer

Sum of first 50 terms = 2350

Work Step by Step

Given sequence = -2, 0, 2, 4................... This is a arithmetic sequence then first term $a_{1}$ = -2 common difference (d) = 4 - 2 = 2 $50^{th}$ term = -2 + (50 - 1)2 = -2 + 100 -2 = 96 Sum of first 50 terms = $\frac{50}{2}$( $a_{1}$ + $a_{50}$) = $\frac{50}{2}$( -2 + 96) = 25$\times$94 = 2350
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