College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Mid-Chapter Check Point - Page 743: 10

Answer

Sum of first ten terms $S_{10}$ = 6820

Work Step by Step

The given sequence = -20, 40, -60, 80,.................... This is a geometric sequence so the sum find by formula $S_{n}$ = $a_{1}$$\frac{1 - r^{n}}{1 - r}$ In the given sequence first term $a_{1}$ = -20 Common ratio (r) = -2 Sum of first ten terms $S_{10}$ =-20$\times$$\frac{1 - (-2)^{10}}{1 - (-2)}$ = -20$\times$$\frac{-1023}{3}$ = -20$\times$ -341 = 6820
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