College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Mid-Chapter Check Point - Page 743: 3

Answer

First term (put n = 1) $a_{1}$ = 5 Second term (put n = 2) $a_{2}$ = -15 Third term (put n = 3) $a_{3}$ = 45 Fourth term (put n = 4) $a_{4}$ = -135 Fifth term (put n = 5) $a_{5}$ = 405

Work Step by Step

Given $a_{1}$ = 5, r = -3 We know $a_{n}$ = $a_{1}r^{(n - 1)}$ First term (put n = 1) $a_{1}$ = 5 $(-3)^{(1 - 1)}$ = 5 $(-3)^{0}$ = 5 Second term (put n = 2) $a_{2}$ = 5 $(-3)^{(2 - 1)}$ = 5 $(-3)^{1}$ = 5 $\times$(-3) = -15 Third term (put n = 3) $a_{3}$ = 5 $(-3)^{(3 - 1)}$ = 5 $(-3)^{2}$ = 5 $\times$9 = 45 Fourth term (put n = 4) $a_{4}$ = 5 $(-3)^{(4 - 1)}$ = 5 $(-3)^{3}$ = 5 $\times$(-27) = -135 Fifth term (put n = 5) $a_{5}$ = 5 $(-3)^{(5 - 1)}$ = 5 $(-3)^{4}$ = 5 $\times$81 = 405
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