Answer
First term (put n = 1) $a_{1}$ = 5
Second term (put n = 2) $a_{2}$ = 2
Third term (put n = 3) $a_{3}$ = -1
Fourth term (put n = 4) $a_{4}$ = -4
Fifth term (put n = 5) $a_{5}$ = -7
Work Step by Step
Given $a_{1}$ = 5, d = -3
We know $a_{n}$ = $a_{1}$ + (n - 1)d
First term (put n = 1) $a_{1}$ = 5 + (1 - 1)(-3) = 5
Second term (put n = 2) $a_{2}$ = 5 + (2 - 1)(-3) = 5 - 3 = 2
Third term (put n = 3) $a_{3}$ = 5 + (3 - 1)(-3) = 5 - 6 = -1
Fourth term (put n = 4) $a_{4}$ = 5 + (4 - 1)(-3) = 5 - 9 = -4
Fifth term (put n = 5) $a_{5}$ = 5 + (5 - 1)(-3) = 5 - 12 = -7
