College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Mid-Chapter Check Point - Page 743: 5

Answer

General term($n^{th}$ term) = 4n - 2 Indicated term $a_{20}$ = 78

Work Step by Step

The given sequence = 2, 6, 10, 14,............;$a_{20}$ From above we observe $a_{1}$ = 2 common difference (d) = 14 - 10 = 10 - 6 = 6 - 2 = 4 General term($n^{th}$ term) = $a_{n}$ = 2 +(n-1)4 = 2+4n-4 = 4n - 2 Indicated term $a_{20}$ = 4$\times$20 - 2 = 80 - 2 = 78
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