Answer
$x \geq \frac{1}{2}$
Work Step by Step
$$5x + 8 \leq 7(1+x)$$
First, we need to simplify the inequality:
$5x + 8 \leq 7 + 7x$
And re-arrange the values:
$8 - 7 \leq 7x - 5x$
$1 \leq 2x$
$\frac{1}{2} \leq \frac{2}{2}x$
$\frac{1}{2} \leq x$; which can also be expressed as $x\geq \frac{1}{2}$
