Answer
a. $4$
b. $4$
c. $\log_{3}(9^{2})=2\log_{3}9$
Work Step by Step
$\log_{b}b^{x}=x$
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a.
Since $81=3^{4},$
$\log_{3}81=\log_{3}3^{4}=4$
b. $ 9=3^{2},\quad$ so
$2\log_{3}9=2\log_{3}3^{2}=2(2)=4$
c. Conclusion:
$\log_{3}(9^{2})=2\log_{3}9$
