Answer
$5ft$ and $\frac{8}{12}$ of an inch as an adult.
Work Step by Step
$$f(x) = 62 + 35log(x-4)$$ where $x$ = girl's age in years and $f(x)$ is the $percentage$ of adult height. Since the girl in this exercise is 4'6", we can write this as 48" + 6" = 54" tall. Now, we can solve for $f(10)$: $$f(10) = 62 + 35log(10-4)$$ $$f(10) = 62 + 35log(6)$$ where $f(10) \approx 89$% of adult height. To find her full adult height, we simply divide her actual height (54") by 89%: $$\frac{54}{0.89} = 60.67 = 60\frac{8}{12}$$ which is $5ft$ and $\frac{8}{12}$ of an inch.