College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.2 - Page 468: 127

Answer

$5ft$ and $\frac{8}{12}$ of an inch as an adult.

Work Step by Step

$$f(x) = 62 + 35log(x-4)$$ where $x$ = girl's age in years and $f(x)$ is the $percentage$ of adult height. Since the girl in this exercise is 4'6", we can write this as 48" + 6" = 54" tall. Now, we can solve for $f(10)$: $$f(10) = 62 + 35log(10-4)$$ $$f(10) = 62 + 35log(6)$$ where $f(10) \approx 89$% of adult height. To find her full adult height, we simply divide her actual height (54") by 89%: $$\frac{54}{0.89} = 60.67 = 60\frac{8}{12}$$ which is $5ft$ and $\frac{8}{12}$ of an inch.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.