College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.2 - Page 468: 145


$\log_{3}40$ is greater.

Work Step by Step

$60 $ is a number between $4^{2}=16$ and $4^{3}=64$, so $\log_{4}60$ is a number between 2 and 3. $40 $ is a number between $3^{3}=27$ and $3^{4}=81$ so $\log_{3}40 $is a number between 3 and 4. Thus, $\log_{3}40$ is greater.
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