Answer
a. 5
b. 5
c. $\log_{2}(8\cdot 4)=\log_{2}8+\log_{2}4$
Work Step by Step
$\log_{b}b^{x}=x$
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a.
Since $32=2^{5},$
$\log_{2}32=\log_{2}2^{5}=5$
b. $ 8=2^{3},\quad 4=2^{2},$ so
$\log_{2}8+\log_{2}4=\log_{2}2^{3}+\log_{2}2^{2}=3+2=5$
c. Conclusion:
$\log_{2}(8\cdot 4)=\log_{2}8+\log_{2}4$
