Answer
False.
To make it true, change the RHS to $\displaystyle \frac{3}{2}$
Work Step by Step
$8$ and 4 are powers of 2.
$8=2^{3},\qquad 4=2^{2}.$
Applying the basic property $\log_{b}b^{x}=x$,
$\log_{2}2^{3}=3$
$\log_{2}2^{2}=2$
So the equation should read
$\displaystyle \frac{\log_{2}8}{\log_{2}4}=\frac{3}{2}$
