Answer
See below.
Work Step by Step
The domain of the function is all the real numbers.
$-3x^2-6x+1=-3(x^2+2x)+1=-3((x+1)^2-1)+1=4-3(x+1)^2$
$(x+1)^2\geq0$, so $4-3(x+1)^2\leq4-0=4$, thus the range is $(-\infty,4]$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 3 - Mid-Chapter Check Point - Page 390: 4
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