Answer
$2x^3-5x^{2} -3x+6$
Work Step by Step
$(2x^4-13x^{3}+17x^{2}+18x-24)\div (x-4)$
$\begin{array}{lllll}
\underline{4}| & 2 & -13 & 17 & 18& -24\\
& & 8 & -20 & -12&24\\
& -- & -- & -- & --\\
& 2 & -5 & -3 & 6& |\underline{0}
\end{array}$
$4$ is a zero,
$(2x^4-13x^{3}+17x^{2}+18x-24)\div (x-4)=2x^3-5x^{2} -3x+6$,
