Answer
$x = -\frac{1}{2}, \frac{2}{3}, \frac{7}{2}$
Work Step by Step
Since the equation is already factorized, we can simply take each factor and equal it to zero as such:
$(2x+1) = 0$, $(3x-2)^{3} = 0$ and $(2x-7)=0$
where, by solving each one individually, we get:
(a)$$2x + 1 = 0$$
$$\frac{2x}{2} = -\frac{1}{2}$$
$$x=-\frac{1}{2}$$
(b)$$\sqrt[3] {(3x - 2)^{3}} = \sqrt[3] 0$$
$$3x - 2 = 0$$
$$\frac{3x}{3} = \frac{2}{3}$$
$$x = \frac{2}{3}$$
(c)$$2x - 7 = 0$$
$$\frac{2x}{2} = \frac{7}{2}$$
$$x = \frac{7}{2}$$