College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Mid-Chapter Check Point - Page 390: 21


See below.

Work Step by Step

Let $x$ be one of the numbers, then the other is $-18-x$, then their product is $-x^2-18x$. The maximum value is at $x=-\frac{b}{2a}=-\frac{18}{2\cdot(-1)}=9.$ Hence the maximum value is $f(9)=-(9)^2-18(9)=-243.$
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