Answer
See below.
Work Step by Step
The domain of the function is all the real numbers.
$-x^2-4x+5=-(x^2+4x)+5=-((x+2)^2-4)+5=9-(x+2)^2$
$(x+2)^2\geq0$, so $9-(x+2)^2\leq9-0=9$, thus the range is $(-\infty,9]$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 3 - Mid-Chapter Check Point - Page 390: 3
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