College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 635: 42

Answer

$176$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given summation expression, $ \displaystyle\sum_{i=3}^6 (2i^2+1) ,$ substitute $ i $ with the values from $ 3 $ to $ 6 $ and then simplify the expression. $\bf{\text{Solution Details:}}$ Substituting $ i $ with the numbers from $ 3 $ to $ 6 ,$ the given expression evaluates to \begin{array}{l}\require{cancel} (2(3)^2+1)+(2(4)^2+1)+(2(5)^2+1)+(2(6)^2+1) \\\\= (2(9)+1)+(2(16)+1)+(2(25)+1)+(2(36)+1) \\\\= (18+1)+(32+1)+(50+1)+(72+1) \\\\= 19+33+51+73 \\\\= 176 .\end{array}
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