College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 635: 40

Answer

$\dfrac{75}{2}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given summation expression, $ \displaystyle\sum_{i=-1}^2 5(2)^i ,$ substitute $ i $ with the values from $ -1 $ to $ 2 $ and then simplify the expression. $\bf{\text{Solution Details:}}$ Substituting $ i $ with the numbers from $ -1 $ to $ 2 ,$ the given expression evaluates to \begin{array}{l}\require{cancel} 5(2)^{-1}+5(2)^0+5(2)^1+5(2)^2 \\\\= \dfrac{5}{2^1}+5(1)+5(2)+5(4) \\\\= \dfrac{5}{2}+5+10+20 \\\\= \dfrac{5}{2}+35 \\\\= \dfrac{5}{2}+\dfrac{70}{2} \\\\= \dfrac{75}{2} .\end{array}
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