College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 635: 37

Answer

$-18$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given summation expression, $ \displaystyle\sum_{i=2}^5 (6-3i) ,$ substitute $ i $ with the values from $ 2 $ to $ 5 $ and then simplify the expression. $\bf{\text{Solution Details:}}$ Substituting $ i $ with the numbers from $ 2 $ to $ 5 ,$ the given expression evaluates to \begin{array}{l}\require{cancel} (6-3(2))+(6-3(3))+(6-3(4))+(6-3(5)) \\\\= (6-6)+(6-9)+(6-12)+(6-15) \\\\= 0-3-6-9 \\\\= -18 .\end{array}
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