## College Algebra (11th Edition)

$a_{1}$ = 14 $a_{2}$ = 18 $a_{3}$ = 22 $a_{4}$ = 26 $a_{5}$ = 30
Sequence: $a_{n}$ = 4n + 10 To find the nth term of a sequence we substitute n into the sequence and evaluate it. To find the first 5 terms, we substitute 1, 2, 3, 4, and 5 and evaluate. $a_{1}$ = 4(1) + 10 = 14 $a_{2}$ = 4(2) + 10 = 18 $a_{3}$ = 4(3) + 10 = 22 $a_{4}$ = 4(4) + 10 = 26 $a_{5}$ = 4(5) + 10 = 30 The first five terms of the sequence is 14, 18, 22, 26, and 30.