College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 635: 3

Answer

$a_{1}$ = $\frac{6}{5}$ $a_{2}$ = $\frac{7}{6}$ $a_{3}$ =$ \frac{8}{7}$ $a_{4}$ = $\frac{9}{8}$ $a_{5}$ = $ \frac{10}{9}$

Work Step by Step

Sequence: $a_{n}=\frac{n+5}{n+4}$ To find the nth term of a sequence we substitute n into the sequence and evaluate it. To find the first 5 terms, we substitute 1, 2, 3, 4, and 5 and evaluate. $a_{1}$ = $\frac{1+5}{1+4}= \frac{6}{5}$ $a_{2}$ = $\frac{2+5}{2+4}= \frac{7}{6}$ $a_{3}$ = $\frac{3+5}{3+4}= \frac{8}{7}$ $a_{4}$ = $\frac{4+5}{4+4}= \frac{9}{8}$ $a_{5}$ = $\frac{5+5}{5+4}= \frac{10}{9}$ The first five terms of the sequence are $\frac{6}{5}, \frac{7}{6}, \frac{8}{7}, \frac{9}{8}, \text{ and } \frac{10}{9}.$
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