College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.1 - Sequences and Series - 7.1 Exercises - Page 635: 29

Answer

$35$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To evaluate the given summation expression, $ \displaystyle\sum_{i=1}^5 (2i+1) ,$ substitute $i$ with the values from $ 1 $ to $ 5 $ and then simplify the expression. $\bf{\text{Solution Details:}}$ Substituting $i$ with the numbers from $ 1 $ to $ 5 ,$ the given expression evaluates to \begin{array}{l}\require{cancel} (2(1)+1)+(2(2)+1)+(2(3)+1)+(2(4)+1)+(2(5)+1) \\\\= (2+1)+(4+1)+(6+1)+(8+1)+(10+1) \\\\= 3+5+7+9+11 \\\\= 35 .\end{array}
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