## College Algebra (11th Edition)

$x=9$
Raising both sides to the power of $\dfrac{2}{3}$, the solution to the given equation, $x^{3/2}=27 ,$ is \begin{array}{l}\require{cancel} \left( x^{\frac{3}{2}} \right)^{\frac{2}{3}}=\left( 3^3 \right)^{\frac{2}{3}} \\\\ x^{\frac{3}{2}\left(\frac{2}{3}\right)}=3^{3\left(\frac{2}{3}\right)} \\\\ x^{1}=3^{2} \\\\ x=9 .\end{array}