## College Algebra (11th Edition)

$x=\{-8,8\}$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $x^{2/3}=4 ,$ raise both sides to the third power to cancel the denominator of the exponent. Then take the square root of both sides and simplify the resulting radical. $\bf{\text{Solution Details:}}$ Raising both sides of the equation to the third power, the equation above is equivalent to \begin{array}{l}\require{cancel} \left( x^{\frac{2}{3}} \right)^{3}=(4)^{3} \\\\ x^2=64 .\end{array} Taking the square root of both sides and simplifying the radical, the solutions are \begin{array}{l}\require{cancel} x=\pm\sqrt{64} \\\\ x=\pm\sqrt{(8)^2} \\\\ x=\pm8 .\end{array} Hence, the solutions are $x=\{-8,8\} .$