## College Algebra (11th Edition)

$x=0$
We rewrite the 25 on the right side, so that the base is 5 on both sides. $5^{2+2x}=25 \\5^{2+2x}=5^2$ Then we set the exponents equal, because the two sides are equal only if the powers are equal too: $2+2x=2$ $2x=2-2$ $2x=0 \\x=0$