College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 410: 63

Answer

$x=-2$

Work Step by Step

We rewrite both sides, so that the base is $\frac{2}{5}$ on both sides. $(\frac{5}{2})^x=\frac{4}{25} \\(\frac{5}{2})^x=(\frac{2}{5})^2$ By the law of exponents: $\frac{5}{2}^x=\frac{2}{5}^{-x}$. Thus, $(\frac{2}{5})^{-x}=(\frac{2}{5})^2$ Then we set the exponents equal, because the two sides are equal only if the powers are equal too: $-x=2$ $x=-2$
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