## College Algebra (11th Edition)

$x=0$
We rewrite the 8 on the right, so that the base is $2$ on both sides. $2^{3-2x}=8 \\2^{3-2x}=2^3$ Then we set the exponents equal, because the two sides are equal only if the powers are equal too: $3-2x=3$ $3-3 = 2x$ $0=2x \\0=x$